OK...Happy to oblige you...Here is my latest scheme...
I sure hope these pix are better for you all. I use very matched parts per channel, matched with my calibrated VOM and LCR meters. With matched 105,800 Ohm resistors for the HF pole and 2.2 Meg. for the LF pole, these values can only be retained utilizing careful soldering with heat sinks applied liberally to all leads involved while soldering. The capacitors, especially polystyrene types, are very fragile with regards to heat. For the best, lowest tolerance results, measure the parts' values after the soldered parts have cooled down. In order to adhere precisely with mathematical calculations, heat sinking is necessary.
My EQ parts' choices for my mostly stateside pre-RIAA discs, will probably differ from European collectors, like Plato65. I chose to keep the "0" HF Rolloff position "open" for no capacitance across the 105.8K resistor, but this is optional. For the "-8" switched position, I chose 471 pf for a 50 uS HF time constant, close to the -10.5 db@10KHz as requested. If I wanted a -12 db@10KHz for the actual "AES" phono EQ adherence, I would choose 600 pf. If I wanted -11 db @10KHz, I could use 534 pf. These would be switched in, parallel with the 105.8K resistor.
In my units, my "-12" HF position is actually set for -13.7 db@10KHz, adhering closely with the genuine RIAA/New Orthophonic phono EQ. This requires 707 pf, switched in across/parallel to the 105.8K resistor. That provides the needed 75 uS (74.9) uS time constant.
My "-16" position, adhering with "NAB/Columbia LP" phono EQ, requires a 100 uS time constant for -16 db@10KHz. Thus, I chose 945 pf to be switched in across the 105.8K resistor.
For my bass boost/turnover poles, I use a 2.2Meg resistor across the switched in cap:
3200 pf for the "AES" EQ adherence.
For the "New Ortho/RIAA," I use 2450 pf.
For the "NAB/LP" that same 2450 pf and a 750K resistor get switched in across the 2.2Meg.
For the "800" EQ, 1200 pf was chosen. 1150-1200 pf will work splendidly.
Lastly, for this post, how about a quick math refresher, regarding analysis for phono EQ circuits according to the Lipschitz/Jung writings ? I know, it can be boring, but needs to be remembered for these exercises and applications. Let us call the bass boost/turnover resistor 2.2Meg = R1, the rolloff resistor 105.8K = R2. The bass boost/turnover cap is C1 while the HiFreq. rolloff cap we will call C2. Thus:
(R1x R2 divided by R1 + R2) multiplied by (C1 + C2) = Time Constant in uS (microseconds). In order to convert to frequency in Hz, the math constant 159,155 is used, divided by the obtained uS, yields the actual Turnover frequency in Hz.
Noting that the look of simple "product over sum" math methodology for "resistors in parallel" is used, while caps in parallel get added together, the formula for RIAA/New Orthophonic is: 2,200,000 x 105,800 divided by 2,200,000 + 105,800 yields the "multiplier 100,945.44. Then,
100,945.44 x .003157 (which is C1 + C2 or .002450 + .000707 =.003157) = 318.68 uS Turnover time constant, close to the 318 uS (500 Hz) specified by RIAA.
159,155 divided by 318.68 results with the actual +3 db point of Turnover = 499.42 Hz, very close to the 500 Hz turnover as needed for precision RIAA phono EQ. This actual point of turnover, is often referred to as an "asymptote" or transition.
For the "AES" EQ values, the same multiplier 100,945.44 x .003800 = 383.59 uS
159,155 / 383.59 = 415 Hz, adhering nicely with the AES phono EQ needs.
I hope this enlightens all concerned....