Sigh. No, that analysis is 100% incorrect.
You know the rectifier has failed because the B+ STOPS. The solid-state diodes are wired in series with the tube rectifier's pins. The purpose is to take up the slack in reverse voltage, as this stresses a tube rectifier but not the solid-state rectifier. The 0.7 VDC voltage drop from solid-state, by the way, is negligible for B+ so it can be ignored.
All current flows through the tube, cathode to plate. All of the current. Every single electron.
So, no, the voltage does not suddenly rise if the rectifier fails, and there is no safety drawback. The advantage is extension of the tube rectifier's lifespan, always a good thing as rectifier tubes cost real money.