After purchasing my new to me Sansui 9090 I found it is too large to fit in my rack. So I plan on building a shelve unit using steel threaded pipes and flanges screwed into solid oak wood shelves 48" long X 17-20" wide X 1" thick. Would put support spanners at all 4 corners going up 2-3 tiers. My receiver weighs 54 lbs. and turntable probably 5-6 lbs. I was hoping to avoid putting a center support at the 24" mark. Do you think shelve will support 60-65 lbs. without center support?
Any load bearing experts out there?
- Thread starter KiltedCowboy
- Start date
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I think you will be fine. A 48"x17"x1" slab of white oak should deflect 0.01" with a 75 lb center load. A deeper shelf will deflect even less. This is for clear, straight grained wood.
Edit:
I should add that the 0.01" figure is per foot so a 48" long board will sag 0.04" in the center with a 75 lb center load. Since the receiver won't be a load at the very center, the deflection should be less to some degree.
Edit:
I should add that the 0.01" figure is per foot so a 48" long board will sag 0.04" in the center with a 75 lb center load. Since the receiver won't be a load at the very center, the deflection should be less to some degree.
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Securely attached front or rear trim will add to the overall strength.
I doubt 1" thick Oak is going to sag, but if you tend to the anal side, you could always put a small diameter post in the back only - so not in your face in the front. You could also use a small steel sq channel screwed to the underside of the oak - again only in the back for added stiffness.
Best thing would be to find a candidate board and see if there is any flexion at all across the 48" width - I tend to think not.
Best thing would be to find a candidate board and see if there is any flexion at all across the 48" width - I tend to think not.