This circuit is a variation of Fisher's tried and true formulation of having the output tube cathode current power the heaters of certain small signal tubes. In this case however, it is the current flow of the entire receiver drawing current through the small signal tubes -- and of course that 400Ω resistor. As such then the success of the circuit depends on the bias voltage needs of the output tubes (to produce the correct quiescent current) being basically the same voltage that it takes to light the heaters of three 12AX7 tubes wired in series using their 12 volt heater configuration. The 400Ω resistor is there to prevent too much voltage rise with increasing power output from the Class AB1 output stage (an operating mode that has the output stage drawing significantly more current as power output is increased).
But of course, that's the rub -- different output tubes draw different current levels for a give grid bias voltage. So unless you have weak output tubes installed (which would definitely cause your issue), it's a virtually certainty that you have output tubes installed that draw less current for a given grid bias voltage, than the tubes Fisher sold the unit with (large manufacturers could always specify a particular characteristic of the tubes they buy from tube manufacturers, because they purchase so many). So like any cathode biased circuit, the actual bias voltage produced (across the heaters in this case) is a function of equilibrium: current flow through the bias system increases bias voltage until the bias voltage won't allow any more current to flow (I'm targeting the output tubes since they are the largest current sink in the design).
Now if you increase the 400Ω resistor to 1000Ω, that allows for more bias voltage to be developed, but also allows for a greater rise in bias voltage with increasing power output. Short of finding a matched set of output tubes that have the same characteristic that the tubes Fisher used, the best answer is to install a bias control. You'd still need to use matched output tubes, but you'd just set the output tube cathodes to a potential of 36 volts and be done with it.
A bias control would be easy enough to install, only requiring a 5000Ω pot (linear, .5 watt), and a .5 watt 24K resistor. Connect one side of the pot to the -36 volt source. Connect the other side of the pot to one lead of the 24K resistor, and ground the other end of the resistor. Disconnect the 33K resistor supplying bias voltage to the output tubes from the -36 volt source, and connect it to the wiper of the pot -- and that's it.
This arrangement will allow as much bias voltage as before when the wiper of the pot is turned towards the -36 volt source, and as much as about 6 volts less bias as the wiper is turned towards the 24K resistor. Of course this arrangement will do nothing if you have the opposite problem (too much bias voltage with the bias control already turned full towards the -36 volt source) -- all you can do in that instance is get tubes more in keeping with those you have installed now, that don't produce enough bias voltage, and then let the bias control bring them up to speed.
Understand that the small signal tube heaters will do just fine with anything from about -33 to -36 volts across them. Warm up time will increase as the bias voltage is lowered, but the main concern is that with -36 vdc across the three heaters and 400Ω resistor, the correct current draw will then be established to set the correct operating point for the output stage, allowing it to deliver optimum performance.
BTW -- Welcome to AK!
I hope this helps!
Dave