Well, that answered that. I never really could see what R129 was. On this end, it looked by 1.3K, but now that you are indicating that it is 15K, that changes things a little.
With a 400 ohm resistor and a 15K resistor connected in parallel, you get (400 X 15000)/(400+15000) = 390 ohms. 44volts/390 ohms = 113 ma/ 4 tubes = 28 ma per tube. This is a little cool to operate these tubes at.
Using a 350 ohm resistor, that in parallel with a 15K resistor = 342 ohm. With a cathode voltage of 44 volts, this equates to 32 ma per tube, which is should deliver very good performance.
Using a 300 ohm resistor, that would equate to 294 ohms, or 37.5 ma per tube, which would be about the max you'd want the tubes to draw under quiescent conditions.
325 ohms will bias the tubes at 34.5 ma each.
Therefore, anywhere between 325 - 350 ohms should be about ideal. At the current level that this resistor range will cause the output stage to draw, output tube dissipation is about 13 watts per tube, which is just fine for these tubes.
I'm sorry for moving you around on these values, but the slight shift downward is because without anything else to go on, I could only go on what R129 appeared to be, which was 1.3K. Now that you have confirmed the actual value as much higher than that, that has shifted the required value of the "heater resistor" lower to compensate.
If you have a 350 ohm resistor, that should suffice just fine. The resistor will dissipate 5.5 watts, so again, a 20 watt resistor would be optimum.
Dave