relay control circuit modification
As suggested by ecluser, post 49, and further discussed in posts 57 and 58.
As seen in Pic 1 below, left to right:
- new Omron MY4-02-DC24 relay, 24v DC (same part# as original relay)
- new 2sc1213A transistor, Qe26
<schematic attached to post #77 on page 6>
- new 6.8k resistor, Re58
-
circuit modification a 2w, 360 ohm resistor replacing 11v zener diode De8
- (also seen in pic - new FM and PW caps)
And in pic 2:
-
circuit modification a new standard diode (1n4002, 1 amp 100v) attached in parallel with the relay coil
calculations
< if I am off base here somebody please let me know>
The original De8 zener dropped 11v from the 34v rail so the original circuit was giving 23v to the relay coil.
In making a decision as to the size of the resistor which would replace De8 and also determine the voltage applied to the relay coil I considered these factors:
- the original coil received 23v (seems too close to max to me)
- the
relay datasheet has a spec called " Must Operate Voltage" stated as "80% Max". This I interpreted as .8 x 24v = 19.2v, and also made the assumption that the coil would operate correctly at any voltage above 19.2v. Is this correct?
So I played with some numbers and settled on 360 ohms for the resistor to give the relay coil around 21.72v.
The coil's DC resistance, according to the datasheet, is 636 ohms. Rail voltage is 34v. This gives:
- circuit total resistance = 636 + 360 = 996
- total amperage of this circuit = 34/996 = .0341 amps
- voltage drop across the resistor = 360 x .0341 = 12.276v
- power dissipated in the resistor = 12.276 x .0341 = .418w
- voltage drop across relay coil = 34 - 12.276 = 21.724v
Based on the these calculations, I may have gone a bit overboard in selecting a 2w resistor and (especially) a 1 amp diode. Better to err on the side of too much capacity than too little I guess.
<note the pic shows a 390 ohm resistor, it was later changed to 360 ohms>