Here is how I interpret things. This may get a little lengthy so bear with me.
You circuit description seems much different that the schematic I have.
According to my copy, the negative supply rectifier is labeled D5. In addition there are a total of four 18k resistors in the bias supply for the tubes.
That .8 volts is not supplied by D5, as the capacitors C20 and C21 block that negative DC.
The schematic I am using is at
www.berners.ch.
A text summary of the bias circuit is like this:
The -150 line is connected to one end of R54 , R55, R29 and R30. The other end of these resistors are connected to a cap (12uf@250) and to one end of R28, R31, R53, and R56. The other end of R28, R30, R53 and R56 are connected to Pin 5 of the output tubes and to
the cathodes of the 12AZ7.
Now, if the amp matches the schematic at berners, then things are ok. If not, then all bets are off.
Assuming that the amp matches the schematic, here is my take on the whole bias circuit.
WRT to the negative voltage supply for the output tubes, I believe the voltage that you are reading is correct and proper for a chassis without tubes in it. Since there is nothing to draw current through the resistors R53, R54, R55 R56, and R28, R29, R30 and R31, the voltage is going to be more negative than what would be there with tubes installed. Grids draw current. If that negative voltage was very low, (closer to 0 volts) then I would be concerned. A grid with 0 volts on it would turn those outputs into big expensive orange light bulbs.
Since you changed the rectifier from a selenium, you may have to play with things to get the bias voltage just right. My guess is that the values of R54, R55, R29, and R30 will have to be increased a bit. You are still good to go.
What is the upshot of having a bias voltage that is more negative than "normal"? The tube will then be placed deeper or closer into cutoff. While the tubes will last longer, there will likely be an increase in distortion and a lack of power.
WRT the lack of voltages on 3 and 8 of the 12AU7, there is 0 volts there because the tube is not in the circuit. If you look at the schematic, those pins relate to the cathode of the tube and the only connection they have is a single resistor to ground. Since conduction of the tube is required to create the measured voltage on the schematic, that is normal. In other words, the source of that voltage is the tube itself. No tube - No voltage. Again, you are good to go.
Overall summary?
You are good to go and to move on to the next step provided that the schematic and the amp match.