Impedance mismatching and reflections in horns
Okay, I've been trying to read through Augsburger et al with the goal of understanding the huge-to-small peaks and valleys in impedance due to reflections as you move up in frequency. (See the HornResp graph I posted.) I was going to try to type it up as much for my own learning as anything.
Then I picked up the March 2008 AudioXpress, with the big article "How Horns Work" by Bjorn Kolbrek. The graphs there show it really well, and remember that we're talking about something true of almost ALL BASS HORNS to varying degrees (and frequencies. To minimize reflection in a certain frequency range, make the mouth circumference of an exponential horn at least one wavelength at the cutoff frequency of the horn, so that K(Rm)>=1, where Rm is the radius of the mouth.
Let's try that with a 100hz horn. The wavelength can be calculated with the speed of sound etc., but here’s an on-line calculator:
http://www.mcsquared.com/wavelength.htm
Tells us 100hz = 11.3 feet, or about 136 inches.
Circumference = pi(2R), we’re solving for R, assuming a circumference = 100 hz wavelength = 136 inches, divide by Pi = 43.3 inches for diameter or 2 x radius. Think about that. Three and a half feet of DIAMETER for the mouth of a 100 hz horn to minimize reflections! Double that for 50 hz, and again for 25 hz! For comparison, my 30 cu. ft. Jensen boxes have a mouth size of ~36 inches x 32 = 1152 sq inches= equiv circle size of diameter 38.3 inches, circumference = 120.3 inches = a mere 113 hertz. (Another useful calculator, this time for circle calculations:
http://www.csgnetwork.com/circlecalc.html)
That is why I say that it is unfortunately not practical to completely eradicate the reflection problem for BASS horns. Firing into a corner Klipsch-style, though can really help out with the load/impedance matching…