Sir.Byrd
Lunatic Member
YES, that's correct it DOES says 20mV. However, lets be clear that your actually setting a "current".
In the SM procedure your measuring the bias "current" indirectly by way of measuring a "voltage" (mV's) between 2 test points. Those 2 points are across a pair of .33Ω emitter resistors connected from emitter to emitter of the output transistor pair. Since we know the voltage (20mV) and the resistance (.33+.33Ω) we can calculate the current at 30mA.
Oh, that's right. I remember you saying that in my post. I'm using my 517 the same way (for now). It'll be nice when it's all done and back in the system, eh? I am waiting to get some new resistors so I can dial my bias into 20mV. I can only dial it up to 15.1mV max with my Bourns trim pots . . . but I think I may put it back in the system for now while I wait.
Matt,
According to this you are getting about 22.8 mA of current, which is very close to spec. To get current from voltage and resistance you simply divide voltage by resistance, so 15.1/.66=22.878