Check CR6 (16V zener) and R2 (3k/2W).
Check the DC voltage at pin 6 of the IC
I replaced R2 with an appropriate resistor and voltage is now at 15v.
However the negative voltage supply to the op-amp is still at -9.6v.
The output pin of the op-amp is at 12.2VDC.
I dont have all of the output transistors installed, I'm wondering if this is having any effect. I noticed that without Q17 there was no -85 supplied to R2,C2,Cr9...I'm curious as if that could be the same for other parts as well...
Installed remaining transistors, no change. still -44VDC at output. Still -9.6 at pin 4 and 12.2 at pin 6.
Watch out for Bose doing weird things like making B+ connections through the cases of the output transistors.
The +12 at the output of the op amp, while there is a large negative voltage at the output, tells me that the differential amp and/or the VAS transistor is not behaving correctly. The +12, at the output of the op amp, is "instructing"
Q1 to turn off. Q1 might be leaky. Can you measure the voltage across R5 and R6? The voltage should be higher across R6.
Measure the voltage across R9. If there's a voltage > 0.28V, it sounds like Q3 or Q24 might be leaky.
Watch out for Bose doing weird things like making B+ connections through the cases of the output transistors.
The +12 at the output of the op amp, while there is a large negative voltage at the output, tells me that the differential amp and/or the VAS transistor is not behaving correctly. The +12, at the output of the op amp, is "instructing"
Q1 to turn off. Q1 might be leaky. Can you measure the voltage across R5 and R6? The voltage should be higher across R6.
Measure the voltage across R9. If there's a voltage > 0.28V, it sounds like Q3 or Q24 might be leaky.
Alrighty,
Voltage across:
R5 = .65 V
R6 = .84 V
This value (0.2/20 = 10mA), indicates that the differential amp has asked this path to conduct less. The complementary path of R15 (0.75/51 = ~15mA) is trying harder to put some positive current into the bias string. To me, this is indicating that there is a short, or leak on the negative side or an open on the positive side. if the amplifier is not drawing a lot of current, it would point to an open in the positive driver side. If the amplifier does draw a lot of current, that would point to a short or leak on the negative half.R9 = .2 mV
I did replace Q24 as the part that was installed appeared to be a weaker transistor than the part that was supposed to be in there...
You have a negative output offset and the output of the op-amp (pin 6) has +12. These R5/6 voltages make sense. You see that there is more current through R6 than R5. Q2 is turned on harder than Q1. That means that the differential amp (Q1, Q2) is trying to turn off the flow from the negative side. Without making more measurements, it looks like the differential amp is doing it's job.
This value (0.2/20 = 10mA), indicates that the differential amp has asked this path to conduct less. The complementary path of R15 (0.75/51 = ~15mA) is trying harder to put some positive current into the bias string. To me, this is indicating that there is a short, or leak on the negative side or an open on the positive side. if the amplifier is not drawing a lot of current, it would point to an open in the positive driver side. If the amplifier does draw a lot of current, that would point to a short or leak on the negative half.
What is the voltage across R23? Check Q6 for open.
Ah, Q24 is just another output transistor. For troubleshooting, you could run it without that one, if you're concerned about it causing a problem. You can measure R44 and see if it's similar to R's 41, 42, 43, 45, 46.
there are 2 Q 24s on the schematic - it looks like the output Q24 should be Q21 (based on the numbering of the other outputs and that there is no Q21)I measured voltage across R23, I got 0V. Measured either side of the resistor with respect to ground, was -44.5VDC
0V across R23, eh? I would lift one leg of CR7. This will open the positive voltage clamp of Q7. Tell you what, before you lift one leg of CR7, measure the voltage across R34. If you get 0V, go ahead and lift one leg of CR7. If you get something near 1 V (or not 0), record the number and write back.
If Q7 is shorted, you lose all positive drive and the output section cannot fight the offset that exists.
It's a little hard to know, for sure if there's an open causing the offset, or a leaky/shorted path.
Usually, if there's something like a shorted negative output in an amplifier, the differential amp will try to force the positive side to correct the offset. This results in a large current depending on the design.
I think you can go ahead and lift one leg of CR5. That only comes into play (ought to) when the over current sensing is triggered.
I would measure the voltage across R27 (22 ohm). It may indicate that there's a leakage path through Q9
Measuring R27 before removing CR5 yielded 0V. Sheet calls for -83V.
Removed CR5, no change in offset, R27 is still 0V.
Removing CR5 and CR7 disables the current limiting circuitry right?
Does lifting Cr5 and Cr7 disable the current limit circuitry? kinda sorta. It doesn't function (at least the positive half), but there's still some resistive paths into the output point.
0V across R27. Okay, that's helpful.
So, here's what we know:
There's a ~ -43V offset at the output
There's a 15mA current (positive) flowing into the bias string.
There's a 10mA current (negative) flowing into the bias string.
The differential amplifier is trying to force a positive shift into the output.
With this, I think you have a leakage path from the -84 rail to the output line.
Measure the voltage across R's 41~46. I think you'll find a voltage drop across 1 (or more) of those.