I have a C2 Basic with a broken balance pot. While I understand the tried-and-true modification of bridging the connections with 180k resistors (http://www.audiokarma.org/forums/showthread.php?t=509349), I am considering trying to replace the pot with a 200k Bournes linear-taper. The pot will fit the circuit board and should be wired up properly given that the circuit board is inversely wired (e.g. Channel A, pin 1 and Channel B, pin 3 have the same circuit path, while Channel A, pin 3 and Channel B, pin 1 also have the same circuit path). I will, unfortunately, have to modify the shaft as I can only find this pot with a knurled shaft However, I have some questions:
Thanks in advance,
-D
- Am I correct in assuming that the value of the pot should be 200k (as close to 180k as you can get)? This would mean at center-detent (balanced), the resistance between each side would be 100k, which is slightly more than 1/2 of the 180k value of the resistor mod.
- Would this translate to lower output volume from each channel when centered?
- Am I even correct in assuming this should be a linear taper?
Thanks in advance,
-D
Last edited:
