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L-PAD vs POT

bobva

Active Member
whats the difference.......... I've been working on my wharfedale W90D they use 50 ohm POTs.
PIA trying to find the size (diameter wise)but I did find some.
 
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whats the difference.......... I've been working on my wharfedale W90D they use 50 ohm POTs.
PIA trying to find the size (diameter wise)but I did find some.

IMO, they are one and the same.
L-Pads are also referred to as the simple two-resistor circuit used to attenuate. That's because the series/parallel configuration forms a letter L.

However, there is a difference between a rheostat like those used on early AR speakers and pots used as L-Pad in speaker attenuation circuits.
 
whats the difference.......... I've been working on my wharfedale W90D they use 50 ohm POTs.
PIA trying to find the size (diameter wise)but I did find some.

L-pads are a form of lossy matching used for attenuation of typically tweeters. The idea is that the load impedance is stable regardless of the attenuation setting and will not cause undesirable shifts in the crossover corner frequency due to changing impedance.

True POTS in series or in parallel can be used to attenuate drivers too since it is just a variable resistor. The downside is that the attenuation comes at the expense of impedance mismatch. In the series case, the attenuation is basically the product of a voltage divider function.

Interesting is that a resistance such as a pot or resistor in series with a tweeter can cause a rising response vs frequency due to the inductance of the tweeter from the voice coil. With a true ribbon, this obviously wouldn't happen.
 
I didn't want to start a new thread for this simple question. But, is an L-pad physically the same as a pot and simply just the name given to a particular wiring configuration of a pot?

From the drawings I've seen, electrically an 8 ohm l-pad is the same as an 8 ohm pot.

For a an 8-ohm L-pad and an 8-ohm speaker, looking into the L-pad:

Fully open: we have 8 || 8 = 4 ohms
Mid way: we have 4 + 8 || 4 = 6.66 ohms
Fully attenuated: we have 8 ohms

If we connect the input to legs 1 and 3 of a pot and the speaker to legs 2 and 3 of the pot, we get exactly the same impedance looking into the pot as we do the L-pad. I'm a bit confused, is L-pad just a name for wiring a pot in this fashion? The circuit diagrams for and L-pad and pot are drawn differently, but electrically they are equivalent.

These are the diagrams I have seen for an L-pad:
http://www.colomar.com/Shavano/lpad3.gif
 
No, not at all. A pot (potentiometer) is a single, variable resistive element. An L-pad is two resistive elements; one in parallel with the load and the other in series with it. An L-pad need not be variable. Two fixed resistors are often used to "pad down" (attenuate), e.g., the output of a tweeter without altering its frequency response.

Also, the power handling of a "pot" is typically limited - high power applications typically use a rheostat.

so... let's see if we can hotlink these images...

Here's a simple potentiometer:

http://www.beavisaudio.com/techpages/SchematicToReality/fig4.2.gif
fig4.2.gif



Here's an L-pad:

http://www.colomar.com/Shavano/lpad3.gif
lpad3.gif


... and here's the equivalent circuit of a (fixed) L-pad:

http://amps.zugster.net/images/articles/attenuation/lpad.gif
lpad.gif
 
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No, not at all. A pot (potentiometer) is a single, variable resistive element. An L-pad is two resistive elements; one in parallel with the load and the other in series with it. An L-pad need not be variable. Two fixed resistors are often used to "pad down" (attenuate), e.g., the output of a tweeter without altering its frequency response.

Also, the power handling of a "pot" is typically limited - high power applications typically use a rheostat.


That's why I'm confused, I guess an L-pad is in fact just a name given to a circuit that uses two resistors to attenuate the output of a tweeter.

Electrically, you could do this with a single POT, but they aren't suitable for high power applications?
 
you are missing the constant impedance part.

I am confused about that. The impedance seems to change, unless I am missing something fundamental. I quickly worked out the impedance (say at a single frequency) for a speaker (drawn as a box) using both an 8 ohm L-pad and an 8 ohm POT. The impedance varies from 4 ohm to 8 ohm in both cases

Hmm, maybe I made the incorrect assumption that the two resistors are equal to each other? If the first resistor is 4 ohms and the second is 8 ohms, the change in impedance would be smaller. In the same analysis, I would get 4 ohms at no attenuation, 4.6 ohms at mid way, and 4 ohms again at full attenuation.

l-pad.jpg


*Edit* Thanks for your answers, at least I know that a POT and L-Pad are not the same. L-pad = speaker attenuation with two resistors. I was confused by the drawings I have seen of a variable L-pads by incorrectly assuming the resistors drawn where the same.
 
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The windings in the L-pad are equivalent. The double-ended wiper in your sketch is what causes them to balance each other out as the wiper moves across the resistance. The pot's single-ended wiper means that the impedance changes as the wiper moves.

WRT to rheostat vs. pot vs. L-pad. "Rheostat" is the generic name for any variable resistor. L-pads and Pots are both types of rheostats. Labeling gets a bit confused by the fact that pots are often generically labeled as rheostats by the electrical industry (power, motors, heaters, etc.), while the electronic industry pretty much always calls them potentiometers.
 
An 8-ohm L-pad does not have two 8-ohm resistors. EDIT: I wrote that all wrong. Look at your drawings, while using the calculator linked to above, and it will make sense. Look at the left "resistor" in your upper-left drawing.
 
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Did you figure it out? They are the same, they are just much higher resistance than 8 ohms. What are they usually anyway? 1k?
 
If possible, take the L-pad apart (good to clean it anyway) and it will become clear...
 
Did you figure it out? They are the same, they are just much higher resistance than 8 ohms. What are they usually anyway? 1k?

That was the source of my confusion, looking at the diagram provided for the L-pad below. If the two resistors are the same, then it is electrically equivalent to a POT.

I plotted the input impedance of this circuit as a function of 'wiper' position, or knob position, 0 = wiper at top, 1 = wiper at bottom in the diagram. (assuming linear for now) I did this for R1=R2=8 ohms and R1= 4 ohms, R2 = 8 ohms. The input impedance clearly changes. So my diagram drawn a few posts above must be incorrect. I'll figure it out. I might just buy an adjustable l-pad and take it apart to see what it physically is. Figuring out what combination of resistors to use for a non-adjustable L-pad is trivial, I just want to figure out how the adjustable ones work.

l-pad3.jpg


l-pad2.jpg
 
I did this for R1=R2=8 ohms and R1= 4 ohms, R2 = 8 ohms. The input impedance clearly changes.
Do it again for R1=R2=1000 ohms (or 200 or a billion). Ta-daaa ;) edit, er... wait, you'd never want R1 over 8 ohms.. shoot. now I don't know how L-pads work either, or rather what is in them.
 
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So are they an 8-ohm pot ganged to a high-ohm pot? Must be, yeah? How accurate are these things anyway? I hate it when I think I know something and then realize it doesn't add up.
 
Here's the equation for an L-pad:

http://www.diyaudioandvideo.com/Calculator/LPad/Help.aspx

circuit.gif

formula.gif


where:

Z = Total Driver Impedance in Ohms
A = Required Attenuation in -db

A variable L-pad contains two variable resistors rigged in such a way as to provide variable attenutation while maintaining fixed impedance (e.g., 8 ohms); according to the equations above.

Here's a pretty good explanation presented for an 8-ohm L-pad:
http://www.bcae1.com/lpad.htm


Thanks for the links!

The mistake I made was to assume both resistors on both sides of the wiper in the diagram were the same. They actually have to be such that R1 varies directly as the dial position and R2 varies as (1-A)/(A+1) for a dial position A, which varies from 0 to 1.

A decent approximation is two Rheostats ganged together, the first has a resistance of 1/2 the load and the second has a resistance of the load. This would provide an input impedance approximately equal to 1/2 the load impedance. Put a series resistor of 1/2 the load resistance and you are good to go. I bet this is what is inside some L-pads. I'll buy one to rip apart and check :) If this is the case, I'll update the Wikipedia article to be more clear.

Here is the circuit I drew to come up with my conclusion:
lpad-4.jpg
 
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