whats the difference.......... I've been working on my wharfedale W90D they use 50 ohm POTs.
PIA trying to find the size (diameter wise)but I did find some.
whats the difference.......... I've been working on my wharfedale W90D they use 50 ohm POTs.
PIA trying to find the size (diameter wise)but I did find some.
No, not at all. A pot (potentiometer) is a single, variable resistive element. An L-pad is two resistive elements; one in parallel with the load and the other in series with it. An L-pad need not be variable. Two fixed resistors are often used to "pad down" (attenuate), e.g., the output of a tweeter without altering its frequency response.
Also, the power handling of a "pot" is typically limited - high power applications typically use a rheostat.
That's why I'm confused, I guess an L-pad is in fact just a name given to a circuit that uses two resistors to attenuate the output of a tweeter.
Electrically, you could do this with a single POT, but they aren't suitable for high power applications?
you are missing the constant impedance part.
Did you figure it out? They are the same, they are just much higher resistance than 8 ohms. What are they usually anyway? 1k?
If possible, take the L-pad apart (good to clean it anyway) and it will become clear...
Do it again for R1=R2=1000 ohms (or 200 or a billion). Ta-daaaI did this for R1=R2=8 ohms and R1= 4 ohms, R2 = 8 ohms. The input impedance clearly changes.
Here's the equation for an L-pad:
http://www.diyaudioandvideo.com/Calculator/LPad/Help.aspx
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where:
Z = Total Driver Impedance in Ohms
A = Required Attenuation in -db
A variable L-pad contains two variable resistors rigged in such a way as to provide variable attenutation while maintaining fixed impedance (e.g., 8 ohms); according to the equations above.
Here's a pretty good explanation presented for an 8-ohm L-pad:
http://www.bcae1.com/lpad.htm