catrafter
Marantz Specialist
@rBuckner I did something similar once. Fortunately it was on a 5V current limited device!
I posted my 'thesis' on what I think is going on in a PM to you.
I will repost it here just in case I am way off base.
Readers please let me know if I screwed up somewhere.
Tom
13.6V is fine. In fact, every model I have seen that uses this power supply scheme is around that voltage.
Increasing the zener voltage slightly would increase the output voltage but I don't think it will make any difference in the overall operation of the receiver.
H810 is a 14V Zener diode (with a tolerance of course, so it could vary slightly).
R809 is 10Ω (and has a tolerance as well). As H804 conducts, it's base current causes a slight voltage increase across R809 so the base of H804 is equal to the H810 Zener voltage plus whatever the voltage is across R809.
The emitter voltage of H804 is about the base voltage minus the B to E drop (assumed to be 0.6V) of H804 .
To get even more technical, lets assume that all the boards that are connected to J806 (the '14V' output) draw 100mA and H804 has a current gain of 50. (I'm assuming these values!)
That means that the base current of H804 is (roughly) the emitter current divided by the current gain or 100mA/50 = 0.5Ma.
0.5mA current flowing through R809(10Ω) causes a voltage of 10 times 0.5mA or 0.5Volt, so with a 14V zener, plus 0.5V across R809 makes 14.5V
14.5V minus the base to emitter voltage drop of H804 (assumed to be 0.6V) equals the output at J806, 13.9V
Or, zener voltage plus voltage drop across R810 minus the B to E drop of H804 equals the output voltage.
(Vz+VR810) - H804BEV= VJ806
(14 +0.5) - 0.6 = 13.9V
Alright, so I just finished up the PSU and protection circuit.
I did notice that my 14v rail is settling in at around 13.6V, will this be a problem? Seems strange that it is so low (was this way before rebuild too).
I posted my 'thesis' on what I think is going on in a PM to you.
I will repost it here just in case I am way off base.
Readers please let me know if I screwed up somewhere.
Tom
13.6V is fine. In fact, every model I have seen that uses this power supply scheme is around that voltage.
Increasing the zener voltage slightly would increase the output voltage but I don't think it will make any difference in the overall operation of the receiver.
H810 is a 14V Zener diode (with a tolerance of course, so it could vary slightly).
R809 is 10Ω (and has a tolerance as well). As H804 conducts, it's base current causes a slight voltage increase across R809 so the base of H804 is equal to the H810 Zener voltage plus whatever the voltage is across R809.
The emitter voltage of H804 is about the base voltage minus the B to E drop (assumed to be 0.6V) of H804 .
To get even more technical, lets assume that all the boards that are connected to J806 (the '14V' output) draw 100mA and H804 has a current gain of 50. (I'm assuming these values!)
That means that the base current of H804 is (roughly) the emitter current divided by the current gain or 100mA/50 = 0.5Ma.
0.5mA current flowing through R809(10Ω) causes a voltage of 10 times 0.5mA or 0.5Volt, so with a 14V zener, plus 0.5V across R809 makes 14.5V
14.5V minus the base to emitter voltage drop of H804 (assumed to be 0.6V) equals the output at J806, 13.9V
Or, zener voltage plus voltage drop across R810 minus the B to E drop of H804 equals the output voltage.
(Vz+VR810) - H804BEV= VJ806
(14 +0.5) - 0.6 = 13.9V
