FlaCharlie
Super Member
Thanks . . . these are the same formulas I used previously.When drawing load lines, you basically have two lines, one Class-A line, and one steeper Class-B line (and than mirrored obviously for a full sine wave).
I think the easiest explanation of this, can be found on Merlin Blencowe's website; http://www.valvewizard.co.uk/pp.html
So your Class-A power is up till the point the other graph line goes up into Class-B mode, the "kink" in the graph
The maximum output power is just the (maximum) RMS voltage times RMS current P = V * I (or P = E * I, depending where you walk around on this planet)
The RMS voltage is HT-Vmin / 1.41.
HT is the total anode-cathode voltage, Vmin is the voltage at the Vg = 0V line.
The RMS current is; Ipeak (at Vg=0V) / 1.41
So P = Vrms * Irms = ((HT-Vmin) / 1.41) * (Ipeak / 1.41) = (HT-Vmin) * Ipeak / 2.
With the same formula you can calculate the Class-A power.
So before the "kink" in the graph, were now Vmin is the transition point in the graph
A (major) downside of running in Class-A is that things will draw a constant current all the time.
Which means that things get HOT very quickly.
So that is something to keep in mind when choosing which tubes you want to use, don't go for small tubes like EL90/6AQ5, but go for a big sturdy 6V6 for example.
Practically speaking; to run your design more into Class-A mode, just lower the HT voltage somewhat, get an higher primary impedance, and use an higher bias current.
My confusion about the power produced using @PakProtector Douglas' operating points and 2k OT was just based on a miscalculation. So that answers my earlier questions #1 and #2.
I assume he suggested those because he wanted to operate in Class A even though the power output will be lower and more heat will be generated.
So to re-state my Question #3, now in two parts:
Is there a sonic advantage to operating a PP amp in Class A vs. Class B?
Are there measurable, technical, advantages when operating a PP amp in Class A vs. Class B?