<snip> Because the display is capable of showing normal bright segments, I doubt whether the tube has lost its vacuum. It's just not stable at the moment in correlation with the circuitry that feeds the voltages and currents.
<snip>
Ok, with that piece of logic in place, the conclusion is inescapable:
The 0v bias on the heater is stable, and goes DIRECTLY to the tube
The heater AC voltage is stable, and goes DIRECTLY to the tube
The 19.1volts to the individual segments is stable, and goes DIRECTLY to the tube segments
The 66v power from the supply is stable
BUT
it does NOT go directly to the tube.
the circuitry that feeds the voltages and currents
it goes through some resistors.
The 390 ohm 1 watt resistor and the 1.2k ohm 2 watt resistor on the protection assembly awm-163 with the bright / dim switch are in the way.The "funny" thing is that bright is MORE resistance (less pin 10 voltage) and dim is LESS resistance (more pin 10 voltage).
you start off with a "balance" being struck between the internal resistance of the tube and the resistance of these resistors. The expression of this balance is the 34.2v you measure at the awv-002 display board's pin 10.
THE conclusion:
Either the tube is changing
OR
the resistors are changing.
The resistors are common, the tube is not. If changing the resistors does not have an effect, the tube is to blame.
The resistors have (66.2 - 34.2) 32v across them, having a current of (32 / (1200 + 390) ) 0.020 amps ... 20mA. At that point the pair of resistors is dissipating (32 * 0.020) 0.64 watts which the resistors should be handling as they are respectively 1 and 2 watts power dissipation.
At the dim point we have (66.2 - 49.4) 16.8 v across them, a current of (16.8 / (1200 + 390) ) 0.010 amps ... 10mA. At that point the pair of resistors is dissipating (16.8 * 0.010) 0.17 watts.
This means that the resistors aren't being worked hard to their limits.
we have one last trick up our sleeve for testing.
the bright/dim switch has been kept in the bright position all the time by design. now it's either time to take the measurements that you did above with the switch in BOTH positions and see what happens with all the voltages.
(pin 26 will start not being zero!! in the dim position)
bright is MORE resistance (1590 ohms), dim is LESS resistance of 1200 ohms by 390 ohms. Ohms law might reveal if one of those resistors is changing value.
Can you measure (see) the resistors during operation? so instead of measuring pin 10 voltage during bright and dim, you could measure the voltage in between the two resistors? Perhaps at the bright/dim switch itself?
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OR you could replace those two resistors - since your change did come on suddenly which indicates some sort of failure. There could still be something else mechanical (heat related?) happening in that area because nothing has been disturbed since you did the work.
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One other thing to try, but I fear external influences will make this impossible to do, is to take a resistance reading between pins 9 & 10 of the awv-002 display board when cold, and then quickly when hot and dim...