The schematic shows +19v for the stereo indicator lamp circuit at the Power Supply Ind pin, and 30mA on the other side of the lamp. The resistor inside the Power Supply is 560Ω. With 30mA flowing through it the voltage drop across it is 16.8v. Measure the voltage on the cathode of D4 or D3, it is not marked on the schematic anywhere I can see, but I'm thinking about +24vdc, as the filter cap is rated 25vdc.
Assuming 24v, minus 16.8v leaves 7.2v. Pioneer used a lot of 8v rated incandescent lamps, driven by a slight undervoltage. The schematic implies that the input selector switch is in the AM position, so the stereo lamp would be off. The stereo indicator lamp is driven by an open collector transistor. Here is where it get a bit hazy for me, because I am not a Tuner guy, but it looks like the stronger the stereo signal is, the more the transistor conducts, and the brighter the lamp gets. The brightnes to current ratio of an incandescent bulb is nonlinear, so some current can flow but not be enough to light the bulb. An LED has a very different current to brightness curve, so it may not work well in that position. On AK I have seen people use leds in that application the satisfies them, and I have seen others give up and just put an incandescent bulb back in, because they were not happy with an led. So I don't have a good answer for you, only something to think about. I did look at that led datasheet and it recommends 10 - 30 mA current, with an absolute max of 50mA. My SWAG calculation came up with a 620Ω or 680Ω 1W (standard value) resistor.
EDIT: The AK go to guy for bulb/led advice is
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