Jon_Logan
Addicted Member
MarkW is right.No stool was ambushing you, no need to get defensive. I merely pointed out an incorrect statement, and tried to clarify. Note, what you said was not true, and it is still not true. Hence my piping up with the comment that the bridged amp does not see a speaker half the impedance of the non-bridged amp.
Thanks for correcting the link. The earlier link to graphic and parametric equalizers didn't make too much sense in this context. Now, if you had read the link you provided, you'd see something like this mentioned:
This supports exactly what I was trying to communicate to you earlier. When you put two amp channels in series (bridged), it is easy to see you get 2X the voltage. When 2X the voltage is applied to the same load, the result is 2X the current. Your claim that the amp would see half the load would result in 4X the current. But, this is not what happens. Please read that link. A bridged amp does not see half the impedance.
I do certainly agree (as noted in my previous post) that each half of the bridged amp must be stable into one half of the attached load. But, a half of a bridged amp does not make a bridged amp. From the point of view of the bridged amp, it sees the load for what it is.
I essence, I believe we are in agreement. It is just that you erroneously worded your position, twice. Oops, make that thrice.
Here's a little mental exercise for you: If a single-ended amp supplies 8V to an 8ohm load, it will produce 1A of output current. In your world, if a bridged amp supplies 8V to an 8ohm load, it will provide 2A of current. In the real world, the bridged amp suppling 8V to an 8ohm load will provide the same 1A that a single-ended amp will deliver. Wacky, huh? I understand you don't care, but perhaps some day, long into the future, you may think about this.
Single-ended vs. Bridged. A single-ended amplifier producing an 8V (rms) waveform into an 8 ohm load produces 1A of current.
A bridged version of the same amp now produces 16volts across the load. The waveforms are out of phase which produces a virtual ground, or null, in the center of the load. That would be 4 ohms. 8v across 4Ohms in a bridge.