By my figuring, the attenuation is 3.9 and 4.1 dB with a mean of 4 dB.
Dr. Beaker's calcs are correct.
If you average the L-Pad resistance values first, the answer is 4.0002 dB.
Calc'ing each one individually, they are 3.9408 and 4.0600, respectively, and the mean is 4.0004; properly stated to one significant decimal place, it's 4.0 dB in both cases.
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I am analyzing the issue Wayne raised with respect to dissipation in the attenuation and HF compensation resistors R1 and R2. The more the overall attenuation required, and the higher the SPL, the higher that is.
In Jack's E'Wave implementation of Wayne's filter, however, the power dissipation is shared between the filter resistors AND the L-pad, which is providing, nominally, up to 4 dB or more of the attenuation.
Are anyone's R1 or R2 getting hot when E'Wave is played at high levels for long periods? Which one?
I can certainly see that in a commercial product sometimes used in sound reinforcement applications at high SPL, it might be prudent to increase the power dissipation capacity of one or both of the compensation/attenuation filter resistors in systems using low-efficiency woofers, particularly if there is no L-pad doing part of the job.
I have not come to any conclusion yet; may we have some input from those of you actually using the E'Wave circuit, please?