s-petersen
Scott
The step network seems excessive, and there is some ringing, I have to look at the schematic and get back to you, at least both channels are similar. Normally you should not do full power square waves, it's pretty hard on the amp.
The step network seems excessive, and there is some ringing, I have to look at the schematic and get back to you, at least both channels are similar. Normally you should not do full power square waves, it's pretty hard on the amp.
set the output level to about 2 volts peak to peak and see what it does. That will give a better picture without amplifier power output limitations skewing it.




yep, thats fine. Just wasn't sure what the level was running at since an earlier post said something about "full". I wasn't sure if that meant full power or what. Running it way up will skew what you actually see on the scope.
The resistor off the plate won't actually be handling all that much power, but its dealing with a lot of voltage. The higher watt resistor was probably picked more for that reason than any other.
yep, thats fine. Just wasn't sure what the level was running at since an earlier post said something about "full". I wasn't sure if that meant full power or what. Running it way up will skew what you actually see on the scope.
The resistor off the plate won't actually be handling all that much power, but its dealing with a lot of voltage. The higher watt resistor was probably picked more for that reason than any other.
Sorry, I'm confused by the "resistor off the plate" comment,
I was thinking of something else that isn't actually there. For some reason I thought the Dynaco had a resistor and cap from output tube plate back to the pentode and thats what you were talking about. Disregard. Its got just a 390pf cap from the screen.
Ah thank you for clarifying. Now if the 1k resistor does not work well enough for some reason (I'll try that first), does putting there a 1k pot temporarily just on one channel to fine tune a resistance that will give the flattest response an option?
The feedback resistor value is determined by the amount of feedback it provides, in this case 20dB. You can check the amount of feedback with the procedure explained in this thread, comment #48.
https://www.audiokarma.org/forums/index.php?threads/citation-ii-hack.471242/page-3
In this case 1K should provide the correct amount.
Only then should the square wave response be fine tuned by adjusting the value of the phase-lead cap across the feedback resistor. Start with the original value in the schematic.
You generally don't tinker with the feedback level as a way of adjusting the amp's frequency response.
- 1k
- 180Ohm res
- 1k
- 180Ohm res
-1k
- 180Ohm res
- 1k
- 180Ohm res180Ohm replaced with 1KOhm. I put new waveform followed by the old waveform (with 180Ohm resistor) for ease of comparison. Here are the results:
100Hz:
View attachment 2698932 - 1k View attachment 2698947 - 180Ohm res
1KHz:
View attachment 2698928 - 1k View attachment 2698944- 180Ohm res
10KHz:
View attachment 2698930 -1k View attachment 2698945 - 180Ohm res
20KHz:
View attachment 2698931 - 1k View attachment 2698946 - 180Ohm res