Let me see if I have this right.
The AC current is induced across the transformer from the primary windings to the secondary ones and is amplified by the windings ratio. When measured from one end of the winding to chassis ground the voltage will be half that of the voltage measured across the windings themselves. This is because the center tap to ground is connected precisely half way through the windings. This AC voltage is then applied to the plates of the rectifier causing their polarity to flip-flop from positive to negative 60 times per second. The cathode, being heated by the aptly named heaters begins to sweat electrons like a swede in a sauna. Each plate in turn attracts the electrons as they go from positive to negative. This drop in electrons from the cathode creates a positive current which flows from the rectifier to and through the primary winding to the plate of the 6K5 output tube. The cathode, once again sitting in its Swedish sauna begins sweating electrons which are vacuumed up by the single plate which is always positive as it is fed by the high voltage B+. Said electron flow being modulated by the grid and screen of the 6K5 since their voltages are being modulated by the Black Magic Voodoo (with a possible pinch of live sacrifice) coming from upstream.
This much I think I understand. My understanding starts to break down with the lack of AC power needed to energize the secondary of the output transformer. Is it possible that a negative current flows from the plate to the opt, combining with the B+ flowing towards the 6K5 to create an AC current that can flow through the 0.01 mf cap thus creating an AC circuit though and back around to the opt? Or does the -DC voltage come from the cathode through the 20, 10, 10 mf caps (one or more of them being smoothing caps?) and on to the transformer circuit creating AC voltage that way? This doesn’t make much sense to me either as the cathode is creating a +DC current and I need a -DC current and only the 20 mf cap is connected to the Cathode and only the two 10 mf caps are in anyway connected to the opt.
Neither of these sound correct to me but I’m currently unable to get past this point as any semblance of understanding just flies out the window.
Please tell me a get part marks for trying.

The AC current is induced across the transformer from the primary windings to the secondary ones and is amplified by the windings ratio. When measured from one end of the winding to chassis ground the voltage will be half that of the voltage measured across the windings themselves. This is because the center tap to ground is connected precisely half way through the windings. This AC voltage is then applied to the plates of the rectifier causing their polarity to flip-flop from positive to negative 60 times per second. The cathode, being heated by the aptly named heaters begins to sweat electrons like a swede in a sauna. Each plate in turn attracts the electrons as they go from positive to negative. This drop in electrons from the cathode creates a positive current which flows from the rectifier to and through the primary winding to the plate of the 6K5 output tube. The cathode, once again sitting in its Swedish sauna begins sweating electrons which are vacuumed up by the single plate which is always positive as it is fed by the high voltage B+. Said electron flow being modulated by the grid and screen of the 6K5 since their voltages are being modulated by the Black Magic Voodoo (with a possible pinch of live sacrifice) coming from upstream.
This much I think I understand. My understanding starts to break down with the lack of AC power needed to energize the secondary of the output transformer. Is it possible that a negative current flows from the plate to the opt, combining with the B+ flowing towards the 6K5 to create an AC current that can flow through the 0.01 mf cap thus creating an AC circuit though and back around to the opt? Or does the -DC voltage come from the cathode through the 20, 10, 10 mf caps (one or more of them being smoothing caps?) and on to the transformer circuit creating AC voltage that way? This doesn’t make much sense to me either as the cathode is creating a +DC current and I need a -DC current and only the 20 mf cap is connected to the Cathode and only the two 10 mf caps are in anyway connected to the opt.
Neither of these sound correct to me but I’m currently unable to get past this point as any semblance of understanding just flies out the window.
Please tell me a get part marks for trying.
