shacky
Addicted Member
There is no "hole" caused by removing a pot. Further, you have it backwards. When you remove a pot you raise the net resistance and this decreases the xover frequency.
Regards,
Jerry
This doesn't make sense to me. How can removing the pot increae resistance? The pot is 15 OHM's no? Removing it would be 0 OHM's wouldn't it?
Here's a piece of previous discussion of 15 OHM Pots vs. 8 OHM LPads:
Quote:
Originally Posted by Upnorth
I've used the Parts Express 16 ohm l-pads with good results on the AR2ax speakers. Although on my AR5's I used the original 15 ohm pots recovered from earlier projects. I know some people don't like fixing the originals as some are well worn out. If you ask there are a ton of originals out there that are restoreable which I think are a much better fit. Just my 2 cents.
Aha, I knew someone would chime in that they found a good replacement! Yes, 16 ohms is close enough to 15 as to make no noticeable difference.
Fotno, the way the equations for crossover frequency work out, if you halve the impedance of the load (in this case the lpad is the load) then the crossover frequency doubles. It is inversely proportional.
Frequency= 1 / (2 x 3.14159 x Capacitance x Impedance). When you divide 1 by a number, if you lower that number you divide by; the result is a higher number. 1/2 is greater than 1/4.
__________________
Warren


