There is a current flowing from the anode of the first diode, through the second diode and then thru the resistor to the base of the transistor. Some of that base current is bypassed by the adjustable resistor VR606.
So in this series string we have two diodes (for a drop of 0.6 each or 1.2 volts), the drop across the added resistor, and the base emitter drop of the transistor (0.6 volts). Without the added resistor that adds up to about 1.8 volts. We need a bit more than that to turn on the following stages. We get that extra voltage via the drop across that added resistor - the higher that resistor value, the more voltage will drop across it; hence the higher the bias voltage (collector (or 'point A') to emitter of TR605).
Clear as mud?
I totally gapped that lower ohms means less resistance...duh! Remembered as soon as I posted! And I'm starting to get voltage drop, bias, and how it will turn on circuits. Going to switch the resistor now.




