I also do not think there are many differences between the GWH-148 and GWH-146 boards.
But on all broken amplifiers, all these transistors overheat . There should be some reason for this
There is. we just haven't found it, yet. Different voltages mean different currents flowing, some currents are enough to smoke out resistors.
The transistors if NOT initially damaged, are definitely not improved with the greater heat exposure.
Save the originals (record exactly where they came from), if we blow up replacements, when we are completely finished and all is understood about the repairs, they can easily go back in.
I'm trying to establish a sequence of voltage tests to find which sections to fix first. This was started by changing the 150 ohm resistor to a pair of 75 ohm resistors to get a reasonable feedback source without the output transistors connected. With this reasonable feedback source on the older NSA amps I would then get the system to correctly balance the output at 0.000v.
Without the feedback, the amp would slam into either the positive rail or the negative rail. Very difficult to find fixes under those conditions.
Then at least when we find the OTHER reason for that amp being "railed" and fix it, the 0.000v will tell us of our success.
Everything from Q1 through Q29 & the Q1 driver have to be working correctly for the amplifier to balance at 0.000v
Back on post #43, I drew an orange "box" around a group of circuits, Q25 & Q27 (Q26, Q28) . They are current sources, and we check them along with Q7 & Q15 to see that they are working correctly. All four (q7, q15, q25, q27) are current sources / sinks that operate independently (almost) of the amp' feedback loop.
how? Voltage readings: emitter base and collector.
I am going to use an easier one as an example, the Q7 current source:
R13 (6800 ohms) is connected to -60v and to the emitter of Q7 at -19.2v, 19.2v across 6800 ohms = 2.82 milliamps current.
R11 (22k), D1 & R9 (10k) are connected between -60v and ground, and the junction of D1 & R9 sets the base bias voltage, which should be -18.6v under proper operation. In other words the base voltage is 0.6v more than the emitter voltage on this NPN transistor..
the next transistors Q9 & Q11 (q10, q12) and their heat dissipation are set by just a 10,000 ohm resistor and are not easily disturbed.
Then we check Q15 (Q16) for proper operation. .
Q15 is a npn transistor, with emitter at -58.7v, through R37 100 ohms to the -60v rail. 60 - 58.7 = 1.3v across 100 ohms is 13mA.
(heat is 0.013a x (emitter v 58.7 - collector v 1.9) = 0.738w)
R35 (220), D3 & R33 (22k) are connected between -60v and ground, and the junction of D3 & R33 sets the base bias voltage, which should be -58.1v under proper operation. In other words the base voltage is also 0.6v more than the emitter voltage on this NPN transistor..
Q15 feeds the NSA stage of q17, q19, VR1, STV-4H diode, q21, q23 which develop the positive and negative base voltages to run the pre-driver / driver / output transistor string.
Q25 & Q27 set the operating points for q17 & q19 (Q25) on the positive side and q21, q23 (Q27) on the negative side. Q13 is the other half of this stage and carries in the audio.
Q25 is a pnp current source and Q27 is an npn current source.
They share the base biasing scheme, R51 (1.3k) R55 (47k) VR3 (100k) R53 (1.3k) connected between the +60v and -60v rails.
Q25 emitter is connected to +60 through 1000 ohms.
Q27 emitter is connected to -60 through 1000 ohms.
Their collector outputs are connected together by a string of diodes and resistors: R101 (100) D11, D13, D15, D17, R103(100).
Their currents should be the same due to the resistor values and shared biasing arrangement.
The test is that the emitter voltage is 0.6v less than the base voltage.
Accuracy in voltage readings is enhanced by using the -60v rail for black dmm lead for npn transistor Q27, and +60v rail for black dmm lead for PNP transistor Q25.
power dissipation is calculated by (R47volts / R47 ohms) milliamps x (Q25 emitter voltage - Q25 collector voltage.)
Get this circuitry working, and finding a pre-driver or driver fault when it's being fed the correct base voltage becomes considerably easier. This base drive voltage also determines the heat being pushed through those transistors and emitter resistors.
One COULD fall back on "old tried and true", checking every resistor out of circuit, every capacitor out of circuit, every diode and transistor in a smart tester.
Now, that's a heck of a load, it's not intended to be digested in one lump, but rather to break it down in small sections and be studied. I hope I have spotted and fixed all the typos.